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Actual: Example 1 If (x 1, y – 2) = (3, 1), find the values of x and y. (x 1, y – 2) = (3, 1) Since the ordered pairs are equal, corresponding elements are
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Consider, (1 i) y 2 (6 i) = (2 i)x. y 2 iy 2 6 i = 2x ix. (y 2 6) i(y 2 1) = 2x ix. Comparing the real parts, we get. y 2 6 = 2x. 2x y 2 6 = 0 (i) Comparing the imaginary parts, we get. y 2 1 = x. x y 2 1 = 0 (ii) Subtracting the eq. (ii) from (i), we get. 2x y 2 6 (x

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Medication Dosage Info ; Age, Dimetapp Cold Allergy (Elixir Chewable tabs) ; 1 y, Don't Give ; 1-2 y, 1/2 tsp (2.5cc) or 1/2 tab (on medical advice only) ; 2-

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(2) – p(–1) p. 1. 2. 9. Find p(0), p(1), p(–2) for the following polynomials : (i) p(x) = 10x – 4x2 – 3. (ii) p(y) = (y 2) (y

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Here, ( x 1, y 1 ) = ( − 4, 4 ), ( x 2, y 2 ) = ( 6, − 5 ) and a : b = 2 : 3 . Substitute in the formula. The coordinates of C are.

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( y 1 y ) 2. Explanation;. Hint: y 2 1 y 2 = ( y 1 y ) 2 - 2 × y × 1 y [a2 b2 = (a b)2 – 2ab]. = ( y 1 y ) 2 - 2 ≠ ( y 1 y ) 2.

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The variables y 1 and y 2 are the entries y(1) and y(2) of a two-element vector dydt . function dydt = vdp1(t,y) %VDP1 Evaluate the van der Pol ODEs for mu = 1

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Откроем скобки (4 - y)^2 - y(y 1) и приведем подобные слагаемые, а затем найдем значение при y = -1/9. (4 - y)^2 - y(y 1) = 16 - 8y

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y (or the range or dependent variable) changes as well. For example:If x equals 2 in the equation y = x -1, then the value of y is 1: y = 2-1

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